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=7+55H-16H^2
We move all terms to the left:
-(7+55H-16H^2)=0
We get rid of parentheses
16H^2-55H-7=0
a = 16; b = -55; c = -7;
Δ = b2-4ac
Δ = -552-4·16·(-7)
Δ = 3473
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-55)-\sqrt{3473}}{2*16}=\frac{55-\sqrt{3473}}{32} $$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-55)+\sqrt{3473}}{2*16}=\frac{55+\sqrt{3473}}{32} $
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